I am looking for a substution RegEx which prefixes all words with a caret, except when followed by a bracket. E.g. "func(x)=y" must be replaced by "func(^x)=^y" .
I came up with (in Python code):
re.sub(r'([A-Za-z][A-Za-z0-9_]*)([^(]|$)', r'^\1\2', 'func(x)=y')
but that does not work. "f(x)=y" is replaced correctly, but it fails when the word before the bracket has more characters.
I suspect it can be done with a single substitution, but I can't figure it out. I guess my solution does not work because the first bracketed regular expression is not greedy enough. What am I doing wrong?
I came up with (in Python code):
re.sub(r'([A-Za-z][A-Za-z0-9_]*)([^(]|$)', r'^\1\2', 'func(x)=y')
but that does not work. "f(x)=y" is replaced correctly, but it fails when the word before the bracket has more characters.
I suspect it can be done with a single substitution, but I can't figure it out. I guess my solution does not work because the first bracketed regular expression is not greedy enough. What am I doing wrong?
